c++: alias template of non-template class [PR112633]
The entering_scope adjustment in tsubst_aggr_type assumes if an alias is dependent, then so is the aliased type (and therefore it has template info) but that's not true for the dependent alias template specialization ty1<T> below which aliases the non-template class A. In this case no adjustment is needed anyway, so we can just punt. PR c++/112633 gcc/cp/ChangeLog: * pt.cc (tsubst_aggr_type): Handle empty TYPE_TEMPLATE_INFO in the entering_scope adjustment. gcc/testsuite/ChangeLog: * g++.dg/cpp0x/alias-decl-75.C: New test.
This commit is contained in:
parent
a53da3a213
commit
3f266c84a1
2 changed files with 14 additions and 0 deletions
|
@ -13976,6 +13976,7 @@ tsubst_aggr_type (tree t,
|
|||
if (entering_scope
|
||||
&& CLASS_TYPE_P (t)
|
||||
&& dependent_type_p (t)
|
||||
&& TYPE_TEMPLATE_INFO (t)
|
||||
&& TYPE_CANONICAL (t) == TREE_TYPE (TYPE_TI_TEMPLATE (t)))
|
||||
t = TYPE_CANONICAL (t);
|
||||
|
||||
|
|
13
gcc/testsuite/g++.dg/cpp0x/alias-decl-75.C
Normal file
13
gcc/testsuite/g++.dg/cpp0x/alias-decl-75.C
Normal file
|
@ -0,0 +1,13 @@
|
|||
// PR c++/112633
|
||||
// { dg-do compile { target c++11 } }
|
||||
|
||||
struct A { using type = void; };
|
||||
|
||||
template<class>
|
||||
using ty1 = A;
|
||||
|
||||
template<class T>
|
||||
using ty2 = typename ty1<T>::type;
|
||||
|
||||
template<class T>
|
||||
ty2<T> f();
|
Loading…
Add table
Reference in a new issue