
When stopped inside an inline function, trying to jump to a different line of the same function currently results in a warning about jumping to another function. Fix this by taking inline functions into account. Before: Breakpoint 1, function_inline (x=510) at jump-inline.cpp:22 22 a = a + x; /* inline-funct */ (gdb) j 21 Line 21 is not in `function_inline(int)'. Jump anyway? (y or n) After: Breakpoint 2, function_inline (x=510) at jump-inline.cpp:22 22 a = a + x; /* inline-funct */ (gdb) j 21 Continuing at 0x400679. Breakpoint 1, function_inline (x=510) at jump-inline.cpp:21 21 a += 1020 + a; /* increment-funct */ This was regression-tested on X86-64 Linux. Co-Authored-by: Cristian Sandu <cristian.sandu@intel.com> Approved-By: Andrew Burgess <aburgess@redhat.com>
30 lines
944 B
C
30 lines
944 B
C
/* Copyright 2021-2023 Free Software Foundation, Inc.
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This program is free software; you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation; either version 2 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program. If not, see <http://www.gnu.org/licenses/>. */
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__attribute__((always_inline))
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static void inline
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function_inline (int x)
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{
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int a = x;
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a += 1020 + a; /* increment-funct. */
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a = a + x; /* inline-funct. */
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}
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int
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main ()
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{
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function_inline (510);
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return 0; /* out-of-func. */
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}
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