57b7402d20
This changes skip_fortran_tests to invert the sense, and renames it to allow_fortran_tests.
57 lines
1.8 KiB
Text
57 lines
1.8 KiB
Text
# Copyright 2020-2023 Free Software Foundation, Inc.
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 3 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/> .
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# Test for GDB printing a pointer to a type containing a buffer.
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require allow_fortran_tests
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standard_testfile ".f90"
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load_lib fortran.exp
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if {[prepare_for_testing ${testfile}.exp ${testfile} ${srcfile} \
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{debug f90}]} {
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return -1
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}
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if ![fortran_runto_main] {
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return -1
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}
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# Depending on the compiler being used, the type names can be printed
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# differently.
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set real4 [fortran_real4]
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gdb_breakpoint [gdb_get_line_number "Break Here"]
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gdb_continue_to_breakpoint "Break Here"
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gdb_test "print buffer" \
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" = \\(PTR TO -> \\( Type l_buffer \\)\\) $hex"
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gdb_test "ptype buffer" \
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[multi_line \
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"type = PTR TO -> \\( Type l_buffer" \
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" $real4 :: alpha\\(:\\)" \
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"End Type l_buffer \\)" ]
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gdb_test "ptype buffer%alpha" "type = $real4 \\(5\\)"
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# GDB allows pointer types to be dereferenced using '*'. This is not
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# real Fortran syntax, just something extra that GDB supports.
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gdb_test "print *buffer" \
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" = \\( alpha = \\(1\\.5, 2\\.5, 3\\.5, 4\\.5, 5\\.5\\) \\)"
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gdb_test "ptype *buffer" \
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[multi_line \
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"type = Type l_buffer" \
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" $real4 :: alpha\\(5\\)" \
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"End Type l_buffer" ]
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gdb_test "ptype (*buffer)%alpha" "type = $real4 \\(5\\)"
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